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4x^2+8x-480=0
a = 4; b = 8; c = -480;
Δ = b2-4ac
Δ = 82-4·4·(-480)
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7744}=88$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-88}{2*4}=\frac{-96}{8} =-12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+88}{2*4}=\frac{80}{8} =10 $
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